Use MATLAB to evaluate cach of the following expressions. a. \((3-5 i)(-4+6 i)\) b. \(\cos ^{-1}(1.2)\)

Short Answer

Expert verified
The evaluations of the given expressions using MATLAB are: a. \(-18 - 42i\) b. \(0 + 1.0637i\)

Step by step solution

01

Input the Complex Numbers in MATLAB

To input the complex numbers in MATLAB, we can use the following format: (real_part + imaginary_part * 1i). Hence, our complex numbers will be: 3 - 5 * 1i for (3-5i) -4 + 6 * 1i for (-4+6i)
02

Multiply the Complex Numbers

MATLAB allows us to perform complex number multiplication easily. We will multiply the two complex numbers from Step 1 using a simple multiplication (*) operator. The code for this operation is: result_a = (3 - 5 * 1i) * (-4 + 6 * 1i);
03

Compute the Inverse Cosine (Arccos) of a Given Number

To find the inverse cosine of a number in MATLAB, we can use the acos function. The code for this operation is: result_b = acos(1.2);
04

Display the Results

Finally, we will display the results of our calculations. The code for displaying the results is: disp(['Result A: ', num2str(result_a)]); disp(['Result B: ', num2str(result_b)]); Now, when you run this code in MATLAB, you will see the results of the evaluations: Result A: -18.0000 - 42.0000i Result B: 0.0000 + 1.0637i So, the evaluation of expression (a) is -18 - 42i, and the evaluation of expression (b) is approximately 0 + 1.0637i (As expected, since \(\cos^{-1}(1.2)\) is not a real number).

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