Write a MATLAB program to evaluate the function $$ y(x)=\ln \frac{1}{1-x} $$ for any user-specified value of \(x\), where \(x\) is a number \(<1\) (note that in is the natural logarithm, the logarithm to the base e). Use an if structure to verify that the value passed to the program is legal. If the value of \(x\) is legal, calculate \(y(x)\). If not, write a suitable error message and quit.

Short Answer

Expert verified
To write a MATLAB program to evaluate the function \(y(x) = \ln\frac{1}{1-x}\) for a user-specified value of \(x\), where \(x < 1\), follow these steps: 1. Request user to input a value for \(x\): `x = input('Enter a value for x (< 1): ');` 2. Check if the input value is legal using an `if` structure, i.e., if \(x < 1\). 3. Calculate and display \(y(x)\) if the value of \(x\) is legal: `y = log(1 / (1 - x)); fprintf('y(x) = %.2f\n', y);` 4. Display an error message and quit the program if the value of \(x\) is not legal: `fprintf('Error: The value of x must be less than 1.\n'); return;` The combined MATLAB script is as follows: ```matlab % Request user-specified value of x x = input('Enter a value for x (< 1): '); % Check if the input value is legal if x < 1 % Calculate y(x) y = log(1 / (1 - x)); % Display the calculated value fprintf('y(x) = %.2f\n', y); else % Display error message and quit fprintf('Error: The value of x must be less than 1.\n'); return end ```

Step by step solution

01

Request the user-specified value of \(x\)

Begin by requesting the user to input a value for \(x\). Use the `input()` function to get the value from the user. Here's how: ```matlab x = input('Enter a value for x (< 1): '); ```
02

Check if the input value is legal

Use an `if` structure to check if the input value is less than 1. If it's not less than 1, we will handle it in the next step. ```matlab if x < 1 % Proceed to calculate y(x) else % Display error message and quit end ```
03

Calculate \(y(x)\) if the value of \(x\) is legal

If the value of \(x\) is less than 1, we can calculate \(y(x) = \ln\frac{1}{1-x}\). Then, use `fprintf` to display the computed value. ```matlab y = log(1 / (1 - x)); fprintf('y(x) = %.2f\n', y); ```
04

Display an error message and quit if the value of \(x\) is not legal

If the value of \(x\) is not less than 1, display an error message using `fprintf` and quit the program using `return`. ```matlab fprintf('Error: The value of x must be less than 1.\n'); return ``` Now, let's put all the steps together in a single MATLAB script. ```matlab % Request user-specified value of x x = input('Enter a value for x (< 1): '); % Check if the input value is legal if x < 1 % Calculate y(x) y = log(1 / (1 - x)); % Display the calculated value fprintf('y(x) = %.2f\n', y); else % Display error message and quit fprintf('Error: The value of x must be less than 1.\n'); return end ```

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Example 3.3, we wrote a program to evaluate the function \(f(x, y)\) for any two user-specified values \(x\) and \(y\). where the function \(f(x, y)\) was defined as follows. $$ f(x, y)=\left\\{\begin{array}{llll} x+y & x \geq 0 & \text { and } & y \geq 0 \\ x+y^{2} & x \geq 0 & \text { and } & y<0 \\ x^{2}+y & x<0 & \text { and } & y \geq 0 \\ x^{2}+y^{2} & x<0 & \text { and } & y<0 \end{array}\right. $$ The problem was solved by using a single if construct with 4 code blocks to calculate \(f(x, y)\) for all possible combinations of \(x\) and \(y\). Rewrite program funxy to use nested if constructs, where the outer construct evaluates the value of \(x\) and the inner constructs evaluate the value of \(y\).

The tangent function is defined as \(\tan \theta=\sin \theta / \cos \theta\). This expression can be evaluated to solve for the tangent as long as the magnitude of \(\cos\) \(\theta\) is not too near to 0 . (If \(\cos \theta\) is 0 , evaluating the equation for \(\tan \theta\) will produce the non-numerical value Inf.) Assume that \(\theta\) is given in degrees, and write the MATLAB statements to evaluate \(\tan \theta\) as long as the magnitude of \(\cos \theta\) is greater than or equal to \(10^{-20}\). If the magnitude of \(\cos \theta\) is less than \(10^{-20}\), write out an error message instead.

Write a program that allows a user to enter a string containing a day of the week ("Sunday," "Monday," "Tuesday," etc.) and uses a switch construct to convert the day to its corresponding number, where Sunday is considered the first day of the week and Saturday is considered the last day of the week. Print out the resulting day number. Also, be sure to handle the case of an illegal day name! (Note: Be sure to use the 's' option on function input so that the input is treated as a string.)

The cost of sending a package by an express delivery service is \(\$ 10.00\) for the first two pounds, and \(\$ 3.75\) for cach pound or fraction thereof over two pounds. If the package weighs more than 70 pounds, a \(\$ 10.00\) excess weight surcharge is added to the cost. No package over 100 pounds will be accepted. Write a program that accepts the weight of a package in pounds and computes the cost of mailing the package. Be sure to handle the case of overweight packages.

Assume that the complex function \(f(t)\) is defined by the equation $$ f(t)=(0.5-0.25 i) t-1.0 $$ Plot the amplitude and phase of function \(f\) for \(0 \leq t \leq 4\).

See all solutions

Recommended explanations on Psychology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free